A Career in Civil Engineering

English,Essay Topic:Assignment 9 – Resumes RESUME (Insert addresses, E-mail addresses and telephone contacts) CAREER OBJECTIVES To do my best with the aim of attaining best possible outcome for an organization. To carry out duties allocated to me keenly, proficiently and with care in any difficult working environment. To work with and around people who will assist me explore myself fully and realize my potential. To work with great asset and dedication to an organisation so as to attain the companies target. To make use of and expand my full potential with an opportunity for professional growth based on performance. To make the most of every opportunity those comes and make it an achievement. I intend to build a career with top environmental corporate with dedicated and committed people. To make sure I leave behind a positive impact in whichever company that I work in. KEY COMPETENCES Excellent communication skills both oral and written Good leadership, organisational and teamwork skills. High level of professionalism. Active listener – Willing to learn and listen Good interpretation of complex data (Trigonometry, Geometry). Flexible, and able to move around from place to place in duty. Good innovative thinking capabilities. Physical Stamina for Outdoor Work Actively creative with continual acquisition of new skills and knowledge. Elaborate mathematical and analytical skills Ability to deliver desired results within a located time or with the available resources. Good risk assessment and management skills Excellent skills in giving out advices. Excellent Information Technology skills PERSONAL INTEREST A well organized individual used to working under minimal supervision, communicates well both in writing and orally, enjoys working in a humanitarian environment, punctual ,reliable and willing to learn with good academic record and strong capacity for directorial growth, self motivated with an outgoing personality and determination to succeed. I believe my interests and skills offer a strong foundation for a good career in Civil Engineering. I like being the mediator in times of conflict between groups or individuals. I am a good problem solver. I seek the chance to combine my interest and creativity in Physics to create and construct. I am drawn by the prospect of being able to interpret and translate ideas that are abstract into physical reality, and of using science to understand solutions that are innovative. My interest in Civil Engineering came at a young age when I visited some tall buildings back within our country. I have keen interest in the awesome potential that Civil Engineering has in reshaping the environment, pushing the boundaries of physical possibilities, while on the other hand making a true impact by solving problems that are practical. I am interested in going deeper into civil engineering and get even Masters and PhD credentials. EDUCATIONAL BACKGROUND PROFESSIONAL EXPERIENCE Place of Internship if any (Insert) Extracurricular Activities Attending seminars and technological quiz competitions. Taking part in youth festivals. Attending Guest talks and slide shows. Project presentation. Participating in debates and essay competitions. Participating in talent shows. Watching and taking part in drama. Singing. Referees (Insert) Mr. 1………………. Place of work…….. Address and other contacts…………… Mrs. 2………………….. Place of work…….. Address and other contacts…………… Dr. 3……………………….. Place of work…….. Address and other contacts…………… Work cited 44 Resume Writing Tips. Daily Writing Tips. N.p., n.d. Web. 26 Nov. 2012. . Sample Resume – Civil Engineer Resume. Enterprise IT Solutions and Services | Publishing, IT, Education, Energy, Insurance: Exforsys. N.p., n.d. Web. 26 Nov. 2012. .

Pythagorean Quadratic

Pythagorean Theorem and Quadratic Equation Introduction Discovered and developed by scientist and mathematician, Pythagoras (c. 570 BC – c. 495 BC),‘Pythagorean Theorem’ is a widely applied mathematical statement which illustrates the relation of the three sides of a right triangle that consists of two legs and a longest side, known as the hypotenuse. In equation, it is given by —
c2 = a2 + b2
where the variables ‘a’ and ‘b’ refer to the length measures of the right triangle’s legs while the variable ‘c’ pertains to the hypotenuse. Applications of Pythagorean Theorem are recognized in various fields of maths such as algebra, trigonometry, and calculus.
Problem 98: Buried Treasure
Ahmed has half of a treasure map, which indicates that the treasure is buried in the desert 2x + 6 paces from Castle Rock. Vanessa has the other half of the map. Her half indicates that to find the treasure, one must get to Castle Rock, walk x paces to the north, and then walk 2x + 4 paces to the east. If they share their information, then they can find x and save a lot of digging. What is ‘x’?
Solution:
By Pythagorean Theorem, x2 + (2x + 4)2 = (2x + 6)2
— x2 + 4×2 + 16x + 16 = 4×2 + 24x + 36
Combining similar terms,
— x2 + 16x – 24x + 16 – 36 = 0
Reduces to Quadratic Equation: x2 – 8x – 20 = 0
where the left side can be factored into (x – 10) * (x + 2) = 0
Then by Zero-Factor Rule: x – 10 = 0 and x + 2 = 0
Isolating ‘x’ in each equation gives x = 10 and x = -2
Taking the positive value, x = 10 paces
Since the Pythagorean Theorem is given by c2 = a2 + b2 then, each of the expressions ‘x’, ‘2x + 4’, and ‘2x + 6’ representing the sides of the right triangle which encloses the route to the buried treasure may be plugged into the Pythagorean equation such that (2x + 6)2 = x2 + (2x + 4)2 where ‘2x + 6’ paces refers to the measure of the longest side. Then expanding the binomials (2x + 6)2 and (2x + 4)2 yields 4×2 + 24x + 36 and 4×2 + 16x + 16, respectively. Upon combining like terms in the compound equation formed, the resulting equation turns out quadratic with x2 – 8x – 20 = 0.
By factoring the trinomial, x2 – 8x – 20 becomes the product (x – 10) * (x + 2). Through zero-factor property, each factor may be equated to zero to have x – 10 = 0 and x + 2 = 0, correspondingly. Solving completely, ‘x’ can be isolated on one side of each equation, becoming x = 10 and x = -2. It is logical to use positive values, so in this case, take x = 10. This means from Castle Rock to the place where the treasure is buried, Ahmed can walk 2*(10) + 6 or 26 paces to access the treasure or Vanessa can walk 10 paces heading north first then 2*(10) + 4 or 24 paces going east to be brought to the treasure spot.
Conclusion
Apparently, ‘Pythagorean Theorem’ proves useful in solving the specified problem which may be put into an illustration of a closed three-sided figure. Since there are distances covered northward and eastward, a 90-degree angle forms out of these segments, so that a right triangle is eventually created once the hypotenuse is drawn to connect the initial point (origin) and the final point (end). Such may be used in comparing the practicality of taking a straight route (along the hypotenuse) to the impracticality of taking two paths (shorter legs) which would consume more time of travel.

Solve each of the trigonometric equations exactly # 21 25 29 33

In Exercises 19-36, solve each of the trigonometric equations exactly on 0 s 0 lt; 27.
TIAS
19. 2sin(20) = V3
20. 2cos
= -V2
21
3 tan(20) – V/3 = 0
No solu
from
23. 2cos(20) + 1 = 0
24. 4csc(20) + 8 = 0
25.
V/3 cot
NI
– 3 = 0
27. tan?0 – 1 = 0
28. sin?0 + 2sin0 + 1 = 0
29
2cos?0 = cos0
31. csc20 + 3csc0 + 2 = 0 32. cot20 = 1
The cosine
33.
in?0 + 2sin0 = 3
35. 4cos20 – 3 = 0
36. 4sin?0 = 3 + 4sin 0
Trigonometry

Solve each of the trigonometric

In Exercises 1-18, solve each of the trigonometric equations exactly over the indicated intervals.
cos0 =
V2
0S0 lt; 2T
V2
lan2 of gnibrooos (alost
2
2. sin0 = –
2
,050 lt; 2T
V3
(@)nia, = (9)m
3. sin0 =
V3
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,0$0 lt; 2m
4. cos0 =
2
,0 $ 0 lt; 2mo zobni ovil
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cos0 =
,0$0 lt;2m
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6. sin0 = –
,0 $ 0 lt; 2mowted olens In
7. csco = -2, 0 $ 0 lt; 47
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8. sec0 = -2, 0 = 0 lt; 4T
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9.
gt;tan 0 = 0, all real numbers
10. cot0 = 0, all real numbers
to xabni ovi
11. sin(20) = –
050 lt; 2m
12. cos(20) = V3
,050 lt; 2T
signs ovi
13.
sin
=
all real numbers
Urein calcalate
the solution
14. COS
= -1, all real numbers
15. tan(20) = V3, -27 $ 0 lt; 2T
Substimeibe
16. tan(20) = – V3, all real numbers
gas svilostlot orli otel
17.
sec0 = -2, -2T $0 lt;0
18. csco =
2V/3
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Trigonometry

The height above the ground of a rider on a Ferris wheel can be modelled by the sine function h(x) = 25

Question

The height above the ground of a rider on a Ferris wheel can be modelled by the sine function h(x) = 25

sin(x – 90°) + 27, where h(x) is the height, in metres, and x is the angle, in degrees, that the radius to the rider makes with the horizontal. Show on the table for one revolution of the Ferris wheel as follows:

Then predict and explain the values for a second revolution of the Ferris wheel.

Trigonometry

Using the Sine rule calculate the horizontal and

Question

Using the Sine rule calculate the horizontal and

vertical component forces. Then use any trigonometric calculation to find the resuant force ‘R’ and the angle at which it acts relative to the horizontal ‘r’

I find vectors impossible to understand, I don’t even know how to approach this problem. Is there any simple way of understanding this?

Trigonometry

Need help with a trig exam see document attached

Thank you.

Question

Need help with a trig exam, see document attached.

Thank you.

5.
1 x +0 y +2 z=−7→ x +2 z =−7
0 x+1 y +0 z=9 → y=9 z=t
x+ 2 z=−7 → x +2 t=−7 → x=−7−2t Solution: There are infinitely many solutions. The solutions are ( x , y , z )…
Trigonometry

A mouse on a spring is moving with simple harmonic motion After a time tea the height age of the mouse above its

Question

A mouse on a spring is moving with simple harmonic motion. After a time tea the height age of the mouse above its

rest position is given by the following formulaFind the height of the mass whenDo not round any intermediate compulsions round your answers to the nearest hundredth

h = aces£wt — e} . ET!quot; 211′
Gwen a = 5.4,: = —, t = 3,e = —
1? 1? Substitute above values in given equation, ‘h 54 (BHXE 2)
.. — .035 1? 1? ‘h 54 (h)
u — . CUE 1T h = 5.4 X…
Trigonometry

See question below and the photo for my comments

Perform the

Question

see question below and the photo for my comments.

Perform theSearch 6:13 AM Fri Jul 5
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of /
X Answer = – 2 tax Secx
5.2. 21 w/ help from the website .
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7 7 sinx
1 – Sinx
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1 , 1 – Sinx
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up to this point,
Itsnx
1 – Sinx
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Itsinx /
but …
I don’t know what I am doing here
7 – Siny
– 1+ sinx
7 – Sin’x
I tenx – saf – sin x
Is this right ? I
1 – sinv – ( 1 + sin x ) – 1 – Sin x – 1 – sinx
1 – sin 2 x
7 – sin 2 x
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Sure it is something small I am missing.!

Trigonometry

Please show the step by step on how to solve it Thank you The Capital Wheel at the National Harbor is

Question

Please show the step by step on how to solve it. Thank you.

  1. The Capital Wheel at the National Harbor is

a Ferris wheel with a diameter of 165 feet. If it were to spin at a rate of 2.1 revolutions per minute, what is the linear speed of a point on the outer edge of the wheel, in miles per hour?

  • Find the exact values of the remaining 5 circular functions (cosine, tangent, cotangent, secant, and cosecant) for angle θ, given that cosθ = 4/7 and θ is an angle in the 4th quadrant. Find exact answers, and simplify them.
  • Solve, finding ALL solutions. Express your answer exactly, using radians. Show work.

    Trigonometry

    See attached questions and answers below from my grade 12 advanced functions text which includes trigonometry I

    Question

    See attached questions and answers below from my grade 12 advanced functions text which includes trigonometry. I

    understand the question and answer. For future problems, I know that it’s a good idea to break down given angles, i.e., cos (15) into the remarkable or known angles that are associated with a triangle and then apply the compound angle formulas.

    Can someone please provide a list of the remarkable (or most often used in grade 12 Trig) angles please? Please give the angle values in degrees and radians. I searched google but too many hits came up!

    If you can provide the name of the triangle the angles are from, that would be greatly appreciated too!

    Trigonometry

    1) Factor the expression then use fundamental identities to simplify

    Question

    1) Factor the expression then use fundamental identities to simplify

    Cos^2xsec^2x-cos^2x

    2) Perform the subtraction then use the fundamental identities to simplify

    a) 1/secx+1 – 1/secx-1

    b) tanx- sec^2x/tanx

    Really need help understanding how to do these problems?

    Trigonometry