of 2.5×10-10) is added to 250. mL of
250. mL of an 0.8 M solution of NaAc (sa of the weak acid HAc with the Ka of 2.5×10-10) is added to 250. mL of
What is the chemical reaction?
What will be the concentration of Ac- after dilution?
What is the equilibrium expression of K (Is it a Ka or Kb?) for the reaction of NaAc- and water:
Find the value of the K:
Based on the value of Kb is Ac- a strong base or a weak base?
Based on the value of Ka is HAc a strong acid or a weak acid?
pOH (at equilibrium) = pH (at equilibrium) = ?