250 ML of an 0 8 M solution of NaAc (salt of the weak acid HAc with the Ka

of 2.5×10-10) is added to 250. mL of

Question

250. mL of an 0.8 M solution of NaAc (sa of the weak acid HAc with the Ka of 2.5×10-10) is added to 250. mL of

water.

What is the chemical reaction?

What will be the concentration of Ac- after dilution?

What is the equilibrium expression of K (Is it a Ka or Kb?) for the reaction of NaAc- and water:

Find the value of the K:

Based on the value of Kb is Ac- a strong base or a weak base?

Based on the value of Ka is HAc a strong acid or a weak acid?

ICE table?

pOH (at equilibrium) = pH (at equilibrium) = ?

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